python中怎么利用len（x）补零? 第1页

       x = int(input())  # You can also use list Rs = ""  # Or `if x < 0: x += 256` x = (x + 256) % 256  # Shift 8 times: when x equals 0, Rs automatically gets 0 prefix for i in range(8):     Rs = str(x & 1) + Rs     x >>= 1  print(Rs)     

       for i in range(8 - len(Rs)):     Rs.insert(0, 0)     

       # python --version all print("{:0>8}".format(Rs)) # python --version >= 3.6 print(f"{Rs:0>8}")     

                print         (         f         "{(x + 256) % 256:0>8b}"         )